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If you think that all the segments in a tablespace are approximately of the same size, and that they ll grow in a similar fashion, you can choose the UNIFORM extent size option If you do this, you can select a few extent sizes, create all your tablespaces with one of these uniform extent sizes, and allocate objects to the tablespaces based on their size Traditionally, Oracle DBAs worried about the number of extents in a segment You should be more concerned about the size of the extents, though, since extent size has a bearing on the read and write performance of a segment For example, if you choose a very small UNIFORM extent size, the database can t prefetch data or do multiblock reads, thus adversely impacting performance.

In other words, a list partitioned table without a DEFAULT partition will implicitly impose a constraint much like a check constraint on the table: ops$tkyte@ORA10G> insert into list_example values ( 'VA', 'data' ); insert into list_example values ( 'VA', 'data' ) * ERROR at line 1: ORA-14400: inserted partition key does not map to any partition.

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Oracle suggests the following extent size guidelines, if you wish to set the extent sizes yourself: 64KB for small segments 1MB or medium segments 64MB for large segments Under the AUTOALLOCATE option, Oracle will manage the extent size automatically The extent size starts at 64KB and is progressively increased to 64MB by the database The database automatically decides what size the new extent for an object should be, based on the segment s growth pattern Interestingly, Oracle will increase the extent size for an object automatically as the object grows! Autoallocate is especially useful if you aren t sure about the growth rate of an object and you would like Oracle to deal with it..

When hash partitioning a table, Oracle will apply a hash function to the partition key to determine in which of the N partitions the data should be placed. Oracle recommends that N be a number that is a power of 2 (2, 4, 8, 16, and so on) to achieve the best overall distribution, and we ll see shortly that this is absolutely good advice.

If you know the exact space requirements for your objects, you can choose the UNIFORM extents option, which leads to efficient use of all available space. For example, say you know that your largest tables will consume a lot of space and will therefore need a very high extent size. Create a tablespace with a very large uniform size for such tables. If you aren t sure what extent size will be best, AUTOALLOCATE will let the database determine the extent size but it may waste some space due to the varying size of extents.

PART_1

Hash partitioning is designed to achieve a good spread of data across many different devices (disks), or just to segregate data out into more manageable chunks. The hash key chosen for a table should be a column or set of columns that are unique, or at least have as many distinct values as possible to provide for a good spread of the rows across partitions. If you choose a column that has only four values, and you

Oracle recommends that unless all the objects in a tablespace are of the same size, you should use the

AUTOALLOCATE feature. In addition to the simplicity of management, the AUTOALLOCATE option for extent sizing can potentially save you a significant amount of disk space, compared to the UNIFORM extent size option.

PART_2

use two partitions, then all the rows could quite easily end up hashing to the same partition, obviating the goal of partitioning in the first place! We will create a hash table with two partitions in this case. We will use a column named HASH_KEY_COLUMN as our partition key. Oracle will take the value in this column and determine the partition this row will be stored in by hashing that value: ops$tkyte@ORA11GR2> CREATE TABLE hash_example 2 ( hash_key_column date, 3 data varchar2(20) 4 ) 5 PARTITION BY HASH (hash_key_column) 6 ( partition part_1 tablespace p1, 7 partition part_2 tablespace p2 8 ) 9 / Table created. Figure 13-2 shows that Oracle will inspect the value in the HASH_KEY_COLUMN, hash it, and determine which of the two partitions a given row will appear in.

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